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  • 标题:Simple Affine Extractors using Dimension Expansion
  • 本地全文:下载
  • 作者:Matt DeVos, Ariel Gabizon
  • 期刊名称:Electronic Colloquium on Computational Complexity
  • 印刷版ISSN:1433-8092
  • 出版年度:2009
  • 卷号:2009
  • 出版社:Universität Trier, Lehrstuhl für Theoretische Computer-Forschung
  • 摘要:Let \F be the field of q elements. An \emph{\afsext{n}{k}} is a mapping D : \F n \ar \B such that for any k -dimensional affine subspace X \F n , D ( x ) is an almost unbiased bit when x is chosen uniformly from X . Loosely speaking, the problem of explicitly constructing affine extractors gets harder as q gets smaller and easier as k gets larger. This is reflected in previous results: When q is `large enough', specifically q = ( n 2 ) , Gabizon and Raz \cite{GR05} construct affine extractors for any k 1 . In the `hardest case', i.e. when q = 2 , Bourgain \cite{Bour05} constructs affine extractors for k n for any constant (and even slightly sub-constant) 0"> 0 . Our main result is the following: Fix any k 2 and let d = 5 n k . Then whenever 2\cdot d^2"> q 2 d 2 and d"> p = c ha r ( \F ) d , we give an explicit \afsext{n}{k}. For example, when k = n for constant 0"> 0 , we get an extractor for a field of constant size ( 1 2 ) . Thus our result may be viewed as a `field-size/dimension' tradeoff for affine extractors. Although for large k we are not able to improve (or even match) the previous result of \cite{Bour05}, our construction and proof have the advantage of being very simple: Assume n is prime and d is odd, and fix any non-trivial linear map T : \F n \F . Define Q R : \F \B by Q R ( x ) = 1 if and only if x is a quadratic residue. Then, the function D : \F n \B defined by D ( x ) \triangleq Q R ( T ( x d )) is an \afsext{n}{k}. Our proof uses a result of Heur, Leung and Xiang \cite{HLX02} giving a lower bound on the dimension of products of subspaces.
  • 关键词:derandomization , extractors
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